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=800R-0.25R^2
We move all terms to the left:
-(800R-0.25R^2)=0
We get rid of parentheses
0.25R^2-800R=0
a = 0.25; b = -800; c = 0;
Δ = b2-4ac
Δ = -8002-4·0.25·0
Δ = 640000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$R_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$R_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{640000}=800$$R_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-800)-800}{2*0.25}=\frac{0}{0.5} =0 $$R_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-800)+800}{2*0.25}=\frac{1600}{0.5} =3200 $
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